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Chapter 1 Vector Analysis: Problem 1.15
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Problem 1.15 Calculate the divergence of the following vector functions:
(a) $v_a = x^2\hat{i}+3xz^2\hat{j}-2xz\hat{k}$
(b) $v_b = xy\hat{i}+2yz\hat{j}+3zx\hat{k}$
(c) $v_c = y^2\hat{i}+(2xy+z^2)\hat{j}+2yz\hat{k}$
Solution:
Divergence of a vector function $\vec{F} = F_u\hat{u}+F_v\hat{v}+F_w\hat{w}$ in a coordinate system where $\vec{dl} = f du\hat{u}+gdv\hat{v}+hdw\hat{w}$ is given by:
$$\vec{\nabla}\cdot \vec{F} = \frac{1}{fgh}\big[\frac{\partial}{\partial u}(ghF_u)+\frac{\partial}{\partial v}(fhF_v)+\frac{\partial}{\partial w}(fgF_w)\big]$$
In Cartesian Coordinate System:
$$\vec{dl} = dx\hat{i}+dy\hat{j}+dz\hat{k}$$
$$\vec{\nabla}\cdot \vec{F} = \frac{\partial}{\partial x}(F_x)+\frac{\partial}{\partial y}(F_y)+\frac{\partial}{\partial z}(F_z)$$
In Cylindrical Coordinate System:
$$\vec{dl}
= ds\hat{s}+sd\phi\hat{\phi}+dz\hat{k}$$
$$\vec{\nabla}\cdot \vec{F} = \frac{1}{s}\big[\frac{\partial}{\partial s}(sF_s)+\frac{\partial}{\partial \phi}(F_{\phi})+\frac{\partial}{\partial z}(sF_z)\big]$$
In Spherical Coordinate System:
$$\vec{dl} = dr\hat{r}+rd\theta\hat{\theta}+r\sin\theta d\phi\hat{\phi}$$
$$\vec{\nabla}\cdot \vec{F} =
\frac{1}{r^2\sin\theta}\big[\frac{\partial}{\partial r}(r^2\sin\theta F_r)+\frac{\partial}{\partial \theta}(r\sin\theta F_{\theta})+\frac{\partial}{\partial \phi}(rF_{\phi})\big]$$
Now, coming to the question. All the vector functions are given in Cartesian coordinate system.
(a) $v_a = x^2\hat{i}+3xz^2\hat{j}-2xz\hat{k}$
$$\vec{\nabla}\cdot \vec{v_a} = \frac{\partial}{\partial x}(x^2)+\frac{\partial}{\partial y}(3xz^2)+\frac{\partial}{\partial z}(-2xz)$$
$$\vec{\nabla}\cdot \vec{v_a} = 2x+0+(-2x) = 0$$
(b) $v_b = xy\hat{i}+2yz\hat{j}+3zx\hat{k}$
$$\vec{\nabla}\cdot \vec{v_b} = \frac{\partial}{\partial x}(xy)+\frac{\partial}{\partial y}(2yz)+\frac{\partial}{\partial z}(3zx)$$
$$\vec{\nabla}\cdot \vec{v_a} = y+2z+3x = 3x+y+2z$$
(c) $v_c = y^2\hat{i}+(2xy+z^2)\hat{j}+2yz\hat{k}$
$$\vec{\nabla}\cdot \vec{v_c} = \frac{\partial}{\partial x}(y^2)+\frac{\partial}{\partial y}(2xy+z^2)+\frac{\partial}{\partial z}(2yz)$$
$$\vec{\nabla}\cdot \vec{v_a} = 2y+2x+2y = 2(x+2y)$$
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